Two Hundred Versus Eight

Two documents both match the query term kubernetes. The average document length in the index is 500 terms.

doc term frequency document length
S (keyword-stuffed) 200 2000
T (real tutorial) 8 400

BM25 scores the term frequency part as

tftf+k1(1−b+b⋅dlavdl)\frac{tf}{tf + k_1\left(1 - b + b \cdot \frac{dl}{avdl}\right)}

with k1=1.2k_1 = 1.2 and b=0.75b = 0.75. Both documents get the same IDF. What is the ratio of S's term frequency component to T's?

A

About 0.6

B

About 1.1

C

About 25

D

About 3.2