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Shift Count Nine

A transfer runs over a 2.5 Gbit/s path with an 80 ms round trip and no loss.

BDP=2.5×109 bit/s×0.08 s=25 MB\text{BDP} = 2.5 \times 10^9\ \text{bit/s} \times 0.08\ \text{s} = 25\ \text{MB}

The unscaled TCP window field tops out at 65,535 bytes. RFC 7323 multiplies the advertised window by 2s2^{s}, where s is the shift count carried in the Window Scale option and is capped at 14.

What is the smallest s that lets the window cover the bandwidth-delay product?