Invertible Two by Two Mod 11

Work with arithmetic modulo the prime 11, so every entry is one of the 11 residues ${0,1,\dots,10}$ and every non-zero residue has a multiplicative inverse. Consider the $11^4 = 14641$ matrices

$M = \begin{bmatrix} a & b \ c & d \end{bmatrix}, \qquad a,b,c,d \in {0,1,\dots,10}$

$M$ is invertible exactly when $ad - bc \neq 0 \pmod{11}$.

How many of the 14641 matrices are invertible? Answer format: enter an integer.