Where The Log Vanishes

A candidate solves $T(n) = 4T(n/2) + n \lg n$ by saying: "master theorem case 2, so $T(n) = \Theta(n^{\log_2 4} \lg n) = \Theta(n^2 \lg n)$."

Compare $f(n) = n \lg n$ against $n^{\log_b a} = n^2$ and give the correct answer.